1. Compute the following: (30 pts)
a. Track capacity
b. Cylinder capacity
c. Drive capacity
A. Base from the given below:
Number of records: 70,000 records
Size of records: 512 bytes
Disk Characteristics:
Number of bytes per sector: 1024
Number of sector per track: 256
Number of tracks per cylinder: 60
Number of cylinders: 5026
B. Base from the given below:
Number of records: 80,000 records
Size of records: 512 bytes
Disk Characteristics:
Number of bytes per sector: 256
Number of sector per track: 75
Number of tracks per cylinder: 20
Number of cylinders: 5026
2. How many records can be stored per track for the following blocking factors?(30 pts)
a. Block factor = 30
b. Block factor = 40
c. Block factor = 70
Having the following:
• Disk characteristics:
• Size of track: 40 000 bytes
• Non data overhead per block: 600 bytes
File Characteristics:
• Record Size: 200 bytes
3. Given the magnetic disk unit with the following performance, what is the average access time in milliseconds required to read the 6,000 byte length block data recorded in this magnetic disk?
a. Magnetic disk unit performance
i. Storage capacity per track (bytes) 40,000
ii. Revolution speed (revolution/minute) 6,000
iii. Average seek time(milliseconds) 40
4. Given the following magnetic disk unit specifications and conditions of the data subject to storage, how many tracks does the necessary area have when the blocking factor is 40? Here, the area is assigned by track and the file organization is sequential.
a. Magnetic disk unit specifications
i. Storage capacity per track 50,250 Bytes
ii. Inter-block gap 800 Bytes
iii. Record length: 400 Bytes
iv. Number of records: 20, 000 Records
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